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NCTB Aligned33 Formulas

Chemistry Formulas

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Standard formula sheet for Chemistry covering mole concept, molarity, stoichiometry, gas laws, and redox equivalence.

HSC (Paper 1) - Chapter 2: Qualitative Chemistry

2 Formulas
HSCChapter 2 (Paper 1)

Rydberg Formula

রিডবার্গ সমীকরণ • Qualitative Chemistry

1λ=RH(1n12−1n22)\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)
(1)/(λ) = R_H ( (1)/(n_1^2) - (1)/(n_2^2) )
HSCChapter 2 (Paper 1)

Solubility Product

দ্রাব্যতা গুণফল (Ksp) • Qualitative Chemistry

Ksp=[Ay+]x[Bx−]yK_{sp} = [A^{y+}]^x [B^{x-}]^y
K_sp = [A^y+]^x [B^x-]^y

HSC (Paper 2) - Chapter 3: Quantitative Chemistry & Redox

3 Formulas
HSCChapter 3 (Paper 2)

Molarity Equation

দ্রবণের ঘনমাত্রা সূত্র • Quantitative Chemistry & Redox

S=1000×WM×V(mL)S = \frac{1000 \times W}{M \times V (\text{mL})}
S = (1000 * W)/(M * V (mL))
HSCChapter 3 (Paper 2)

Titration Equivalence

টাইট্রেশন সূত্র • Quantitative Chemistry & Redox

V1S1e1=V2S2e2V_1 S_1 e_1 = V_2 S_2 e_2
V_1 S_1 e_1 = V_2 S_2 e_2
HSCChapter 3 (Paper 2)

Titration Equivalence Formula

এসিড-ক্ষার ও রেডক্স টাইট্রেশন সমতা • Quantitative Chemistry & Redox

VA⋅SA⋅eA=VB⋅SB⋅eBV_A \cdot S_A \cdot e_A = V_B \cdot S_B \cdot e_B
V_A * S_A * e_A = V_B * S_B * e_B

💡 Condition: Equivalence relation in volumetric titration where e represents equivalence factor / valence change.

HSC (Paper 2) - Chapter 1: Environmental Chemistry (Gas Laws)

5 Formulas
HSCChapter 1 (Paper 2)

Combined Gas Law

সমন্বিত গ্যাস সূত্র • Environmental Chemistry (Gas Laws)

P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
(P_1 V_1)/(T_1) = (P_2 V_2)/(T_2)

💡 Condition: Combined relationship of pressure, volume, and absolute temperature for a constant gas quantity.

HSCChapter 1 (Paper 2)

Ideal Gas Density Equation

গ্যাস ঘনত্ব সমীকরণ • Environmental Chemistry (Gas Laws)

PM=ρRT  ⟹  ρ=PMRTPM = \rho RT \implies \rho = \frac{PM}{RT}
PM = ρ RT implies ρ = (PM)/(RT)

💡 Condition: Calculates gas density ρ as a direct function of pressure, molecular weight, and temperature.

HSCChapter 1 (Paper 2)

Dalton's Law of Partial Pressures

ডাল্টনের আংশিক চাপ সূত্র • Environmental Chemistry (Gas Laws)

Ptotal=pA+pB+pC,pi=xi⋅Ptotal=nintotalPtotalP_{\text{total}} = p_A + p_B + p_C, \quad p_i = x_i \cdot P_{\text{total}} = \frac{n_i}{n_{\text{total}}} P_{\text{total}}
P_total = p_A + p_B + p_C, p_i = x_i * P_total = (n_i)/(n_total) P_total

💡 Condition: Total pressure of a non-reacting gas mixture equals the sum of component partial pressures.

HSCChapter 1 (Paper 2)

Graham's Law of Diffusion

গ্রাহামের গ্যাস ব্যাপন সূত্র • Environmental Chemistry (Gas Laws)

r1r2=M2M1=ρ2ρ1=t2t1\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} = \sqrt{\frac{\rho_2}{\rho_1}} = \frac{t_2}{t_1}
(r_1)/(r_2) = sqrt((M_2)/(M_1)) = sqrt((ρ_2)/(ρ_1)) = (t_2)/(t_1)

💡 Condition: Rate of effusion/diffusion inversely proportional to the square root of molar mass.

HSCChapter 1 (Paper 2)

Van der Waals Real Gas Equation

ভ্যান ডার ওয়ালস বাস্তব গ্যাস সমীকরণ • Environmental Chemistry (Gas Laws)

(P+an2V2)(V−nb)=nRT\left(P + \frac{an^2}{V^2}\right)(V - nb) = nRT
(P + (an^2)/(V^2))(V - nb) = nRT

💡 Condition: Modifies ideal gas law to account for intermolecular attractions (a) and molecular volume (b).

HSC (Paper 1) - Chapter 4: Chemical Changes & Equilibrium

6 Formulas
HSCChapter 4 (Paper 1)

Equilibrium Constants (Kp & Kc)

ভরক্রিয়া সূত্র ও সাম্যধ্রুবক (Kp ও Kc) • Chemical Changes & Equilibrium

aA+bB⇌cC+dD  ⟹  Kc=[C]c[D]d[A]a[B]b,Kp=pCc⋅pDdpAa⋅pBbaA + bB \rightleftharpoons cC + dD \implies K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}, \quad K_p = \frac{p_C^c \cdot p_D^d}{p_A^a \cdot p_B^b}
aA + bB leftharpoons cC + dD implies K_c = ([C]^c [D]^d)/([A]^a [B]^b), K_p = (p_C^c * p_D^d)/(p_A^a * p_B^b)

💡 Condition: Equilibrium constant expressions in terms of molar concentrations (Kc) and partial pressures (Kp).

HSCChapter 4 (Paper 1)

Relation Between Kp and Kc

Kp ও Kc-এর সম্পর্ক • Chemical Changes & Equilibrium

Kp=Kc(RT)Δn,Δn=(c+d)−(a+b)K_p = K_c (RT)^{\Delta n}, \quad \Delta n = (c+d) - (a+b)
K_p = K_c (RT)^Δ n, Δ n = (c+d) - (a+b)

💡 Condition: Mathematical bridge connecting pressure and concentration equilibrium constants with Δn mole difference.

HSCChapter 4 (Paper 1)

Ostwald's Dilution Law

অসওয়াল্ডের লঘুকরণ সূত্র • Chemical Changes & Equilibrium

Ka=α2C1−α≈α2C  ⟹  α=KaCK_a = \frac{\alpha^2 C}{1 - \alpha} \approx \alpha^2 C \implies \alpha = \sqrt{\frac{K_a}{C}}
K_a = (α^2 C)/(1 - α) approx α^2 C implies α = sqrt((K_a)/(C))

💡 Condition: Degree of ionization α of a weak electrolyte related to concentration C and dissociation constant Ka.

HSCChapter 4 (Paper 1)

Henderson-Hasselbalch (Acidic Buffer)

হ্যান্ডারসন-হ্যাসেলবালখ অম্লীয় বাফার সমীকরণ • Chemical Changes & Equilibrium

pH=pKa+log⁡10[লবণ / Salt][অম্ল / Acid]\text{pH} = \text{pK}_a + \log_{10}\frac{[\text{লবণ / Salt}]}{[\text{অম্ল / Acid}]}
pH = pK_a + log_10frac[লবণ / Salt][অম্ল / Acid]

💡 Condition: Computes pH of weak acid and conjugate base buffer mixtures.

HSCChapter 4 (Paper 1)

Henderson-Hasselbalch (Basic Buffer)

হ্যান্ডারসন-হ্যাসেলবালখ ক্ষারীয় বাফার সমীকরণ • Chemical Changes & Equilibrium

pOH=pKb+log⁡10[লবণ / Salt][ক্ষার / Base],pH=14−pOH\text{pOH} = \text{pK}_b + \log_{10}\frac{[\text{লবণ / Salt}]}{[\text{ক্ষার / Base}]}, \quad \text{pH} = 14 - \text{pOH}
pOH = pK_b + log_10frac[লবণ / Salt][ক্ষার / Base], pH = 14 - pOH

💡 Condition: Computes pOH and derived pH of weak base and conjugate salt buffer systems.

HSCChapter 4 (Paper 1)

Arrhenius Equation for Activation Energy

আরহেনিয়াসের সক্রিয়করণ শক্তি সমীকরণ • Chemical Changes & Equilibrium

k=Ae−Ea/RT  ⟹  ln⁡(k2k1)=EaR(1T1−1T2)k = A e^{-E_a / RT} \implies \ln\left(\frac{k_2}{k_1}\right) = \frac{E_a}{R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)
k = A e^-E_a / RT implies ln((k_2)/(k_1)) = (E_a)/(R)((1)/(T_1) - (1)/(T_2))

💡 Condition: Quantifies temperature dependence of reaction rate constants on activation energy Ea.

HSC (Paper 2) - Chapter 4: Electrochemistry

4 Formulas
HSCChapter 4 (Paper 2)

Faraday's First Law of Electrolysis

ফ্যারাডের তড়িৎ বিশ্লেষণের প্রথম সূত্র • Electrochemistry

W=Z⋅I⋅t=Me⋅F⋅I⋅t=M⋅Qn⋅96500W = Z \cdot I \cdot t = \frac{M}{e \cdot F} \cdot I \cdot t = \frac{M \cdot Q}{n \cdot 96500}
W = Z * I * t = (M)/(e * F) * I * t = (M * Q)/(n * 96500)

💡 Condition: Mass W of substance deposited during electrolysis proportional to total charge Q passed.

HSCChapter 4 (Paper 2)

Standard Cell Potential (EMF)

প্রমাণ গ্যালভানিক কোষের তড়িৎচালক বল • Electrochemistry

Ecell∘=Ecathode (red)∘−Eanode (red)∘E_{\text{cell}}^\circ = E_{\text{cathode (red)}}^\circ - E_{\text{anode (red)}}^\circ
E_cell^circ = E_cathode (red)^circ - E_anode (red)^circ

💡 Condition: Standard EMF of galvanic cell determined from standard reduction potentials of cathode and anode.

HSCChapter 4 (Paper 2)

Nernst Equation for Cell Potential

নার্নস্ট সমীকরণ (কোষ বিভব) • Electrochemistry

E=E∘−2.303RTnFlog⁡10Q=E∘−0.0592nlog⁡10[Products][Reactants]E = E^\circ - \frac{2.303 RT}{nF}\log_{10} Q = E^\circ - \frac{0.0592}{n}\log_{10}\frac{[\text{Products}]}{[\text{Reactants}]}
E = E^circ - (2.303 RT)/(nF)log_10 Q = E^circ - (0.0592)/(n)log_10frac[Products][Reactants]

💡 Condition: Relates cell potential to reaction quotient Q under non-standard concentration conditions.

HSCChapter 4 (Paper 2)

Cell Potential & Gibbs Free Energy

কোষ বিভব ও গিবস মুক্ত শক্তি • Electrochemistry

ΔG∘=−nFE∘=−RTln⁡K\Delta G^\circ = -n F E^\circ = -RT \ln K
Δ G^circ = -n F E^circ = -RT ln K

💡 Condition: Thermodynamic connection between electrochemical cell voltage and free energy change ΔG°.

SSC - Chapter 2: States of Matter (Graham’s Law of Diffusion)

1 Formulas
SSCChapter 2

Graham's Law of Diffusion

গ্রাহামের ব্যাপন সূত্র • States of Matter (Graham’s Law of Diffusion)

r1r2=M2M1=t2t1\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} = \frac{t_2}{t_1}
(r_1)/(r_2) = sqrt((M_2)/(M_1)) = (t_2)/(t_1)

SSC - Chapter 3: Structure of Matter (Isotopes & Bohr Model)

2 Formulas
SSCChapter 3

Average Atomic Mass

গড় আপেক্ষিক পারমাণবিক ভর • Structure of Matter (Isotopes & Bohr Model)

Aavg=∑Ai×pi100A_{\text{avg}} = \sum \frac{A_i \times p_i}{100}
A_avg = Σ (A_i * p_i)/(100)
SSCChapter 3

Bohr Angular Momentum

বোর কৌণিক ভরবেগ • Structure of Matter (Isotopes & Bohr Model)

mvr=nh2πmvr = \frac{nh}{2\pi}
mvr = (nh)/(2π)

SSC - Chapter 6: Concept of Mole & Chemical Calculations

3 Formulas
SSCChapter 6

Unified Mole Formula

সমন্বিত মোল সূত্র • Concept of Mole & Chemical Calculations

n=WM=V22.4=N6.023×1023n = \frac{W}{M} = \frac{V}{22.4} = \frac{N}{6.023 \times 10^{23}}
n = (W)/(M) = (V)/(22.4) = (N)/(6.023 * 10^23)
SSCChapter 6

Solution Molarity

দ্রবণের মোলারিটি • Concept of Mole & Chemical Calculations

W=S×V×M1000W = \frac{S \times V \times M}{1000}
W = (S * V * M)/(1000)
SSCChapter 6

Percentage Composition

শতকরা সংযুতি • Concept of Mole & Chemical Calculations

%Element=n×ArMr×100%\%\text{Element} = \frac{n \times A_r}{M_r} \times 100\%
%Element = (n * A_r)/(M_r) * 100%

SSC - Chapter 7: Chemical Reactions (Oxidation Numbers & Redox)

1 Formulas
SSCChapter 7

Sum of Oxidation Numbers

নিরপেক্ষ যৌগে জারণ সংখ্যার যোগফল • Chemical Reactions (Oxidation Numbers & Redox)

∑(O.N.)=0\sum (\text{O.N.}) = 0
Σ (O.N.) = 0

SSC - Chapter 8: Chemistry & Energy (Bond Energy & ΔH)

1 Formulas
SSCChapter 8

Reaction Enthalpy

বিক্রিয়া তাপ (এনথ্যালপি) • Chemistry & Energy (Bond Energy & ΔH)

ΔH=∑Bbroken−∑Bformed\Delta H = \sum B_{\text{broken}} - \sum B_{\text{formed}}
Δ H = Σ B_broken - Σ B_formed

SSC - Chapter 9: Acid-Base Equilibrium (pH & Titration)

2 Formulas
SSCChapter 9

pH Formula

হাইড্রোজেন আয়ন সূচক • Acid-Base Equilibrium (pH & Titration)

pH=−log⁡10[H+],pH+pOH=14\text{pH} = -\log_{10}[\text{H}^+], \quad \text{pH} + \text{pOH} = 14
pH = -log_10[H^+], pH + pOH = 14
SSCChapter 9

Neutralization Titration

টাইট্রেশন সমীকরণ • Acid-Base Equilibrium (pH & Titration)

VASAa=VBSBb\frac{V_A S_A}{a} = \frac{V_B S_B}{b}
(V_A S_A)/(a) = (V_B S_B)/(b)

SSC - Chapter 11: Mineral Resources: Fossils (Hydrocarbons)

3 Formulas
SSCChapter 11

Alkane General Formula

অ্যালকেন সাধারণ সংকেত • Mineral Resources: Fossils (Hydrocarbons)

CnH2n+2\text{C}_n\text{H}_{2n+2}
C_nH_2n+2
SSCChapter 11

Alkene General Formula

অ্যালকিন সাধারণ সংকেত • Mineral Resources: Fossils (Hydrocarbons)

CnH2n\text{C}_n\text{H}_{2n}
C_nH_2n
SSCChapter 11

Alkyne General Formula

অ্যালকাইন সাধারণ সংকেত • Mineral Resources: Fossils (Hydrocarbons)

CnH2n−2\text{C}_n\text{H}_{2n-2}
C_nH_2n-2

❓ Chemistry Board Examination FAQs

Common questions on formula application and exam problem-solving rules

Q1: What are the four primary formulas for determining the number of moles ($n$)?

The unified mole equation is n=wM=V(L)22.4=NNA=V(L)×Sn = \frac{w}{M} = \frac{V(\text{L})}{22.4} = \frac{N}{N_A} = V(\text{L}) \times S, where ww is mass in grams, MM is molar mass, VV is gas volume at STP in liters, NA=6.023×1023N_A = 6.023 \times 10^{23} (Avogadro constant), and SS is molarity.

Q2: Which formula is used for preparing a standard solution of given molarity?

The preparation formula is W=S×M×V(mL)1000W = \frac{S \times M \times V(\text{mL})}{1000}, where WW is required solute mass in grams, SS is target molarity, MM is solute molar mass, and VV is solution volume in milliliters.

Q3: When is the dilution formula ($V_1 S_1 = V_2 S_2$) applied?

The dilution formula V1S1=V2S2V_1 S_1 = V_2 S_2 is used when adding solvent to dilute a concentrated stock solution. The volume of added water required is given by Vwater=V2−V1V_{\text{water}} = V_2 - V_1.

Q4: What are the formulas and relationships for pH and pOH?

pH=−log⁡10[H+]\text{pH} = -\log_{10}[H^+] and pOH=−log⁡10[OH−]\text{pOH} = -\log_{10}[OH^-]. At 25∘C25^\circ\text{C}, pH+pOH=14\text{pH} + \text{pOH} = 14. A value below 7 denotes acidity, 7 indicates neutrality, and above 7 signifies an alkaline medium.